Optimal. Leaf size=104 \[ -\frac{b x^2 \text{PolyLog}\left (2,-e^{c+d x^2}\right )}{d^2}+\frac{b x^2 \text{PolyLog}\left (2,e^{c+d x^2}\right )}{d^2}+\frac{b \text{PolyLog}\left (3,-e^{c+d x^2}\right )}{d^3}-\frac{b \text{PolyLog}\left (3,e^{c+d x^2}\right )}{d^3}+\frac{a x^6}{6}-\frac{b x^4 \tanh ^{-1}\left (e^{c+d x^2}\right )}{d} \]
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Rubi [A] time = 0.137349, antiderivative size = 104, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 6, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.375, Rules used = {14, 5437, 4182, 2531, 2282, 6589} \[ -\frac{b x^2 \text{PolyLog}\left (2,-e^{c+d x^2}\right )}{d^2}+\frac{b x^2 \text{PolyLog}\left (2,e^{c+d x^2}\right )}{d^2}+\frac{b \text{PolyLog}\left (3,-e^{c+d x^2}\right )}{d^3}-\frac{b \text{PolyLog}\left (3,e^{c+d x^2}\right )}{d^3}+\frac{a x^6}{6}-\frac{b x^4 \tanh ^{-1}\left (e^{c+d x^2}\right )}{d} \]
Antiderivative was successfully verified.
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Rule 14
Rule 5437
Rule 4182
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int x^5 \left (a+b \text{csch}\left (c+d x^2\right )\right ) \, dx &=\int \left (a x^5+b x^5 \text{csch}\left (c+d x^2\right )\right ) \, dx\\ &=\frac{a x^6}{6}+b \int x^5 \text{csch}\left (c+d x^2\right ) \, dx\\ &=\frac{a x^6}{6}+\frac{1}{2} b \operatorname{Subst}\left (\int x^2 \text{csch}(c+d x) \, dx,x,x^2\right )\\ &=\frac{a x^6}{6}-\frac{b x^4 \tanh ^{-1}\left (e^{c+d x^2}\right )}{d}-\frac{b \operatorname{Subst}\left (\int x \log \left (1-e^{c+d x}\right ) \, dx,x,x^2\right )}{d}+\frac{b \operatorname{Subst}\left (\int x \log \left (1+e^{c+d x}\right ) \, dx,x,x^2\right )}{d}\\ &=\frac{a x^6}{6}-\frac{b x^4 \tanh ^{-1}\left (e^{c+d x^2}\right )}{d}-\frac{b x^2 \text{Li}_2\left (-e^{c+d x^2}\right )}{d^2}+\frac{b x^2 \text{Li}_2\left (e^{c+d x^2}\right )}{d^2}+\frac{b \operatorname{Subst}\left (\int \text{Li}_2\left (-e^{c+d x}\right ) \, dx,x,x^2\right )}{d^2}-\frac{b \operatorname{Subst}\left (\int \text{Li}_2\left (e^{c+d x}\right ) \, dx,x,x^2\right )}{d^2}\\ &=\frac{a x^6}{6}-\frac{b x^4 \tanh ^{-1}\left (e^{c+d x^2}\right )}{d}-\frac{b x^2 \text{Li}_2\left (-e^{c+d x^2}\right )}{d^2}+\frac{b x^2 \text{Li}_2\left (e^{c+d x^2}\right )}{d^2}+\frac{b \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{c+d x^2}\right )}{d^3}-\frac{b \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{c+d x^2}\right )}{d^3}\\ &=\frac{a x^6}{6}-\frac{b x^4 \tanh ^{-1}\left (e^{c+d x^2}\right )}{d}-\frac{b x^2 \text{Li}_2\left (-e^{c+d x^2}\right )}{d^2}+\frac{b x^2 \text{Li}_2\left (e^{c+d x^2}\right )}{d^2}+\frac{b \text{Li}_3\left (-e^{c+d x^2}\right )}{d^3}-\frac{b \text{Li}_3\left (e^{c+d x^2}\right )}{d^3}\\ \end{align*}
Mathematica [A] time = 0.100913, size = 138, normalized size = 1.33 \[ \frac{a x^6}{6}-\frac{b \left (d x^2 \text{PolyLog}\left (2,-\sinh \left (c+d x^2\right )-\cosh \left (c+d x^2\right )\right )-d x^2 \text{PolyLog}\left (2,\sinh \left (c+d x^2\right )+\cosh \left (c+d x^2\right )\right )-\text{PolyLog}\left (3,-\sinh \left (c+d x^2\right )-\cosh \left (c+d x^2\right )\right )+\text{PolyLog}\left (3,\sinh \left (c+d x^2\right )+\cosh \left (c+d x^2\right )\right )+d^2 x^4 \tanh ^{-1}\left (\sinh \left (c+d x^2\right )+\cosh \left (c+d x^2\right )\right )\right )}{d^3} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.156, size = 0, normalized size = 0. \begin{align*} \int{x}^{5} \left ( a+b{\rm csch} \left (d{x}^{2}+c\right ) \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{6} \, a x^{6} + 2 \, b \int \frac{x^{5}}{e^{\left (d x^{2} + c\right )} - e^{\left (-d x^{2} - c\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 1.67282, size = 555, normalized size = 5.34 \begin{align*} \frac{a d^{3} x^{6} - 3 \, b d^{2} x^{4} \log \left (\cosh \left (d x^{2} + c\right ) + \sinh \left (d x^{2} + c\right ) + 1\right ) + 6 \, b d x^{2}{\rm Li}_2\left (\cosh \left (d x^{2} + c\right ) + \sinh \left (d x^{2} + c\right )\right ) - 6 \, b d x^{2}{\rm Li}_2\left (-\cosh \left (d x^{2} + c\right ) - \sinh \left (d x^{2} + c\right )\right ) + 3 \, b c^{2} \log \left (\cosh \left (d x^{2} + c\right ) + \sinh \left (d x^{2} + c\right ) - 1\right ) + 3 \,{\left (b d^{2} x^{4} - b c^{2}\right )} \log \left (-\cosh \left (d x^{2} + c\right ) - \sinh \left (d x^{2} + c\right ) + 1\right ) - 6 \, b{\rm polylog}\left (3, \cosh \left (d x^{2} + c\right ) + \sinh \left (d x^{2} + c\right )\right ) + 6 \, b{\rm polylog}\left (3, -\cosh \left (d x^{2} + c\right ) - \sinh \left (d x^{2} + c\right )\right )}{6 \, d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{5} \left (a + b \operatorname{csch}{\left (c + d x^{2} \right )}\right )\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{csch}\left (d x^{2} + c\right ) + a\right )} x^{5}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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